A 3 to 8 Decoder is shown in the figure. Find F(x2; x1; x0)

1
F = ∑ m (1, 4, 7)
2
F = ∑m (0, 2, 3, 5, 6)
3
F = x0 + x1 + x2
4
\(F = \overline {x0 + x1 + x2} \)

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