A square hole is made out of circular lamina, the diagonal of the square being the radius of the circle as shown in the figure. Find the location of the centroid (distance X̅) with respect to point ‘A'.
1
\(\bar{X}=\frac{(\pi-0.75)}{(r-0.5)}\)
2
\(\bar{X}=\frac{r(\pi-0.75)}{(\pi-0.5)}\)
3
\(\bar{X}=\frac{r(\pi-0.75)}{2(\pi-0.5)} \)
4
\(\bar{X}=\frac{(\pi-0.75)}{r(\pi-0.5)}\)