If q is the punching shear resistance per unit area, a is the side of square footing for a column side b, carrying a weight W including the weight of footing, the depth of footing (D) considering the punching shear resistance is
1
\(D = \frac{W(a-b)}{4a^2bq}\)
2
\(D = \frac{W(a^2-b^2)}{4a^2bq}\)
3
\(D = \frac{W(a^2-b^2)}{8a^2bq}\)
4
\(D = \frac{W(a^2-b^2)}{4abq}\)