On subtracting (12a - 9ab - 2) from the sum of (4a  - 7ab - 4b - 5) and (a + 3) (b - 4), we get: 

1
12a - 3ab - b - 15
2
-12a + 3ab - 15
3
-12a + 3ab - b - 15
4
-12a - 15ab -b - 19

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