If x + y + z = 11, x2 + y2 + z2 = 133 and x3 + y3 + z3 = 881, then the value of ∛(xyz) is:

1
-8
2
-6
3
6
4
8

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation