SSC SSC JE Electrical 2025 Mock Test Series (Paper 1 & Paper 2) Digital Electronics Logic Gates and Boolean Algebra
Simplified from of the Boolean expression Y = A̅B̅C̅ + A̅ (B) C̅ + (A)B̅C̅ is:
1
Y = C̅ (A̅ + B)
2
Y = C (A̅ + B̅)
3
Y = C̅ (A̅ + B̅)
4
Y = C̅ (A + B̅)