The power in a series R - L - C circuit will be half of that at resonance when the magnitude of the current is equal to -

1
\(\frac{V}{2 R}\)
2
\(\frac{\mathrm{V}}{\sqrt{3}R} \)
3
\(\frac{\mathrm{v}}{\sqrt{2}R} \)
4
\(\frac{\sqrt{2} V}{R} \)

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