A student is asked to multiply a number K by 5. But he multiplies K by \(\frac{1}{5}\) and gets x% error. Next time he multiplies K by \(\frac{1}{25}\) and gets y% error. Then the percentage increase of y over x is

1
\(3 \frac{1}{3} \%\)
2
\(33 \frac{1}{3} \%\)
3
\(16 \frac{2}{3} \%\)
4
\(24 \frac{4}{5} \%\)

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