Solution for the equation \(\frac{1}{{x + 1}} + \frac{2}{{x + 2}} = \frac{4}{{x + 4}}\), where x+1≠ 0, x+2≠ 0 and x+4≠ 0 using quadratic formula is :
1
{2 + 2\(\sqrt{3}\), 2 - 2\(\sqrt{3}\)}
2
{3 + 2\(\sqrt{3}\), 3 - 2\(\sqrt{3}\)}
3
{-3 + 2\(\sqrt{3}\), -3 - 2\(\sqrt{3}\)}
4
{-2 + 2\(\sqrt{3}\), -2 - 2\(\sqrt{3}\)}
5
Answer not known