Tickets numbered from 1 to 20 are mixed up together and then a ticket is drawn at random. What is the probability that the drawn ticket has a number which is a multiple of 3 or 4?
1
\(\frac{11 }{20 }\)
2
\(\frac{9 }{20 }\)
3
\(\frac{ 1}{ 2}\)
4
\(\frac{3 }{4 }\)