N cadets have to stand in a row. If all possible permutations are equally likely, the probablity of two particular cadets standing side by side is:
1
\(\frac{4 }{ N}\)
2
\(\frac{3 }{ N^2}\)
3
\(\frac{1 }{ 2N}\)
4
\(\frac{2 }{ N}\)
5
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