The probability that 'A' hits a target \(\frac{4}{5}\) and 'B' hits the same target is \(\frac{3}{4}\). If each of them hits once. Then probability that hit only one them is:

1
\(\frac{3}{5}\)
2
\(\frac{6}{7}\)
3
\(\frac{7}{8}\)
4
\(\frac{7}{20}\)

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