A shaft is subjected to combined bending and torsional moments of 6 kN-m and 10 kN-m respectively. The equivalent torque will be equal to

1
\(\sqrt{136}\) kN-m
2
16 kN-m
3
\(\sqrt{16}\) kN-m
4
8 kN-m

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation