If the line 2x + √6y = 2 touches the hyperbola x2 - 2y2 = 4, then the point of contact is

1
(-2, √6)
2
(-5, 2√6)
3
\(\left( {\frac{1}{2},\frac{1}{{\sqrt 6 }}} \right)\)
4
(4, -√6)

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