Teaching Jharkhand (JSSC) TGT (6 to 8) Mock Test 2023-24 Engineering Mathematics Differential Equations Exact Differential Equations
Differential equation \(y^3\frac{dy}{dx}\;+\;x^3=0\), y(0) = 1 has a solution given by y. The value of y(-1) is:
1
-1
2
0
3
1
4
2