The sum of unit fractions of \(\frac{7}{12}\) will be:

1
\(\frac{1}{5}+\frac{1}{7}\)
2
\(\frac{1}{3}+\frac{1}{4}\)
3
\(\frac{1}{2}+\frac{1}{6}\)
4
\(\frac{1}{1}+\frac{1}{12}\)

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