Find the equation of the circle whose end points of the diameter are (- 2, 4) and (4, 2) ? 

1
x2 + y2 - 2x + 6y = 0
2
x2 + y2 + 2x - 6y = 0
3
x2 + y2 - 2x - 6y = 0
4
x2 + y2 + 2x + 6y = 0
5
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