The integral \(\rm \int e^x\left(\frac{x-1}{2x^2}\right)dx\) is equal to
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\(\rm \frac{e^x}{x}+C\), where C is constant of integration
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\(\rm \frac{e^x}{2x}+C\) where C is constant of integration
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exx + C, where C is constant of integration
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x2ex + C, where C is constant of integration
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