tan–1 (1/3) + tan–1 (1/7) + tan–1 (1/13) + ... + 1 tan–1 \(\left(\frac{1}{n^2+n+1}\right)\) + .... ∞ is equal to

1
0
2
π/4
3
π/2
4
2π/3
5
Question Not Attempted

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