If the solution y = y(x) of the differential equation (x4 + 2x3 + 3x2 + 2x + 2)dy – (2x2 + 2x + 3)dx = 0 satisfies \(y(-1)=-\frac{\pi}{4}\), then y(0) is equal to:
1
\(-\frac{\pi}{12}\)
2
0
3
\(\frac{\pi}{4}\)
4
\(\frac{\pi}{2}\)
5
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