If the line y = mx + C is tangent to the circle x2 + y2 = 16 then m =

1
\(\pm \frac{1}{4}\sqrt {C - 16}\)
2
\(\pm \frac{1}{4}\sqrt {C^2 - 16}\)
3
\(\pm \frac{1}{4}\sqrt {C^2 + 16}\)
4
\(\pm \frac{1}{16}({C^2 - 16})\)

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