Mathematics Probability Conditional Probability

If P(B) = \(\frac{3}{5}\), P(A ∣ B) = \(\frac{1}{2}\) and P(A ∪ B) = \(\frac{4}{5}\), then P(A ∪ B)′ + P(A′ ∪ B) =

1
\(\frac{1}{5}\)
2
\(\frac{4}{5}\)
3
\(\frac{1}{2}\)
4
1

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