The rate law for a reaction between the substances A and B is given by Rate = k[A]n[B]m
On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as
1
(m + n)
2
(n − m)
3
2(n − m)
4
\(\frac{1}{2^{(\mathrm{m}+\mathrm{n})}}\)