A ball of mass 'm' is dropped from a height 's' on a horizontal platform fixed at the top of a vertical spring. The platform is depressed by a distance 'h'. The spring constant is (g = acceleration due to gravity)
1
\(\frac{2 \mathrm{mg}(\mathrm{~s}-\mathrm{h})}{\mathrm{h}^{2}}\)
2
\(\frac{2 \mathrm{mg}(\mathrm{~s}+\mathrm{h})}{\mathrm{h}^{2}}\)
3
\(\frac{\mathrm{mg}(\mathrm{~s}-\mathrm{h})}{\mathrm{h}}\)
4
\(\frac{m g(s+h)}{h}\)