A particle of mass m is projected with a velocity v making an angle of 45° with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height h is
1
Zero
2
\(\frac{mV^3}{{4\sqrt2}{g}}\)
3
\(\frac{mV^3}{{\sqrt2}{g}}\)
4
\(m\sqrt{2gh^3}\)