If \(x=a\left(t+\frac{1}{t}\right)\) and \(y=a\left(t-\frac{1}{t}\right)\), then \(\frac{d x}{d y}\) is:

1
\(\frac{x}{y}\)
2
\(\frac{y}{x}\)
3
\(\frac{1}{x}\)
4
1

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