The value of integral \(\int_C \frac{\theta^z}{(z-1)(z-4)} d z\), where C is the circle |z| = 2 is

1
\(\frac{\pi i e}{3}\)
2
\(\frac{2\pi i e}{3}\)
3
\(-\frac{2\pi i e}{3}\)
4
\(\frac{\pi i e}{4}\)

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