In the circuit shown, when the switch is closed, the capacitor is charged with time constant T1 and long after a time, when the switch is open, the capacitor discharge with time constant T2, then \(\frac{T_1}{T_2}\) is
1
1
2
\(\frac{1}{2}\)
3
2
4
\(\frac{1}{4}\)
5
Question Not Attempted