A charged particle q enters a region of uniform magnetic field \(\rm \vec B\) (out of the page) and is deflected through a distance d after travelling a horizontal distance a. The magnitude of the momentum of the particle is
1
\(\rm \frac{1}{2}dB\left[\frac{a^2}{d}+d\right]\)
2
\(\rm \frac{1}{2}qBa\)
3
Zero
4
p = qB \(\sqrt{d^2 + a^2} \)
5
Question Not Attempted