The length of a seconds pendulum at a height h = 2R from earth surface will be (Given R = Radius of earth and acceleration due to gravity at the surface of earth, g = π2 ms–2)
1
\(\rm \frac{2}{9}m\)
2
\(\rm \frac{4}{9}m\)
3
\(\rm \frac{8}{9}m\)
4
\(\rm \frac{1}{9}m\)
5
Question Not Attempted