A block of mass 5 kg is placed on a rough inclined surface as shown in the figure. 


If \(\rm \vec F_1\) is the force required to just move the block up the inclined plane and \(\rm \vec F_2\) is the force required to just prevent the block from sliding down, then the value of \(\rm |\vec F_1|-|\vec F_2|\) is : [Use g =10m /s2 ] 

1
25√3 N
2
50√3 N
3
\( {5\sqrt3}N\)
4
10 N
5
Question Not Attempted

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