Teaching RPSC School Lecturer Mock Test Series 2024 Mathematics Three Dimensional Geometry Distance from a Plane
Find the distance between the straight line \(\frac{{x - 1}}{1} = \frac{{y + 2}}{{\;-1}} = \frac{{z - 3}}{- 3}\) and the plane 4x +13y - 3z + 1 = 0 ?
1
\(\frac{30}{\sqrt {194}}\)
2
\(\frac{35}{\sqrt {194}}\)
3
\(\frac{67}{\sqrt {194}}\)
4
None of these
5
Question Not Attempted