The circuit is driven by a voltage source 40e-4t V. The initial value of the voltage across the capacitor and the initial current through the inductor are both Zero. The current I is:
1
\(i = 40{e^{ - 2t}} - \frac{{40}}{3}{e^{ - t}} - \frac{{80}}{3}{e^{ - 4t}}\)
2
\(i = 40{e^{2t}} + \frac{{40}}{3}{e^t} + \frac{{80}}{3}{e^{ - 4t}}\)
3
\(i = - 40{e^{ - 2t}} - \frac{{40}}{3}{e^{ - t}} - \frac{{80}}{3}{e^{ - 4t}}\)
4
\(i = 40{e^{ - 2t}} + \frac{{40}}{3}{e^{ - t}} + \frac{{80}}{3}{e^{ - 4t}}\)