For \(0<\xi <\frac{1}{\sqrt2},{{\omega }_{r}}\) is equal to:

1
0
2
\(\frac{\omega_n }{\sqrt{1-{{\xi }^{2}}}}\)
3
\({{\omega }_{n}}\sqrt{1-{{\xi }^{2}}}\)
4
\({{\omega }_{n}}\sqrt{1-2{{\xi }^{2}}}\)

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