For the equation \(\frac{{dy}}{{dx}} + 7{x^2}y = 0\), if y(0) = \(\frac{{3}}{{7}}\), then the value of y(1) is
1
\(\frac{7}{3}{e^{ - \frac{7}{3}}}\)
2
\(\frac{7}{3}{e^{ - \frac{3}{7}}}\)
3
\(\frac{3}{7}{e^{ - \frac{7}{3}}}\)
4
\(\frac{3}{7}{e^{ - \frac{3}{7}}}\)