In the above circuit, the switch is closed at t = 0. The expression for current delivered by the source as a function of time is:
1
\(\frac{2}{3}{e^{ - t}} + \frac{1}{4}{te^{ - t}} - \frac{1}{6}{e^{ - \frac{t}{4}}}\;A\)
2
\(\frac{2}{3}{e^{ - t}} + \frac{1}{5} {te^{ - t}} - \frac{1}{6}{e^{ - \frac{t}{4}}}A\)
3
\(\frac{1}{3}{e^{ - t}} + \frac{2}{3}{te^{ - t}} + \frac{1}{4}{e^{ - \frac{t}{4}}}A\)
4
None of the above