If x(t) is as shown in the figure, its Laplace transform is

1
\(\frac{2{{e}^{+5s}}+2{{e}^{-5s}}}{{{s}^{2}}}\)
2
\(\frac{2{{e}^{+5s}}-4+2{{e}^{-5s}}}{{{s}^{2}}}\)
3
\(\frac{2{{e}^{+5s}}-2+2{{e}^{-5s}}}{{{s}^{2}}}\)
4
\(\frac{2{{e}^{+5s}}+4-2{{e}^{-5s}}}{{{s}^{2}}}\)

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