The line current of a 3-ϕ power supply are;

\({I_R} = 3 + j5A\)

\({I_Y} = 2 + j2A\)

\({I_B} = - 2 - j1A\)

The zero sequence current will be

1
(1 + j2) A
2
(5 + j7) A
3
(1 + j4) A
4
(-2 – j1) A

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