For the periodic signal x(t) shown below with period T = 8s, the power in the 10th harmonic is
1
0
2
\(\frac{1}{2}{\left( {\frac{2}{{10\;\pi }}} \right)^2}\)
3
\(\frac{1}{2}{\left( {\frac{4}{{10\pi }}} \right)^2}\)
4
\(\frac{1}{2}{\left( {\frac{4}{{5\pi }}} \right)^2}\)