In a balanced acb sequence, phase a to neutral voltage is V̅an = 100∠20° V. Line-to-line voltage V̅ac is given by

1
ac = 100√3∠50° V
2
ac = 100√3∠-50° V
3
ac = 100∠50° V
4
\({\bar V_{ac}} = \frac{{100}}{{\sqrt 3 }}\angle 150^\circ \;V\)

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