The distance between the parallel planes 4x – 2y + 4z + 9 = 0 and 8x – 4y + 8z + 21 = 0 is

1
\(\frac{1}{4}\)
2
\(\frac{1}{2}\)
3
\(\frac{3}{2}\)
4
\(\frac{7}{4}\)

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