If \(\rm P(A \cup B)=\frac{5}{9}\), \(\rm P(\bar{A} \cup \bar{B})=\frac{13}{27}\), \(\rm P(A)=\frac{11}{18}\), then the odds against the event B are:

1
\(\frac{38}{17}\)
2
\( \frac{7}{57}\)
3
\(\frac{29}{25}\)
4
\( \frac{47}{7}\)

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