If \(\operatorname{Re}\left(\frac{z-1}{2 z+i}\right)=1\), where z = x + iy, then the point (x, y) lies on a
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circle whose centre is at \(\left(-\frac{1}{2},-\frac{3}{2}\right)\).
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straight line whose slope is \(\frac{3}{2}\).
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circle whose diameter is \(\frac{\sqrt{5}}{2}\).
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straight line whose slope is \(-\frac{2}{3}\).