The plates of parallel plate capacitor are separated by d cm. A plane of thickness t cm with dielectric constant k1 is inserted and the remaining space is filled with a plate of dielectric constant k2. If Q is the charge on the capacitor and area of plates is A cm2 each, then potential difference between the plates is
1
\(\frac{Q}{{{\epsilon_0}A}}\left( {\frac{t}{{{k_1}}} + \frac{{d - t}}{{{k_2}}}} \right)\)
2
\(\frac{{4\pi Q}}{A}\left( {\frac{t}{{{k_1}}} + \frac{{d - t}}{{{k_2}}}} \right)\)
3
\(\frac{{4\pi Q}}{A}\left( {\frac{{{k_1}}}{t} + \frac{{{k_2}}}{{d - t}}} \right)\)
4
\(\frac{Q}{{{\epsilon_0}A}}\left( {\frac{{{k_1}}}{t} + \frac{{d - t}}{{{k_2}}}} \right)\)