The solution of \(\rm {dx\over dt}= 3x+8\) will be

1
\(\rm x ={ 1\over 3}e^{(t+c)}-{3\over 8}\)
2
\(\rm x ={ 1\over 3}e^{3(t+c)}-{8\over 3}\)
3
\(\rm x ={ 1\over 3}e^{(t+c)}+{3\over 8}\)
4
\(\rm x ={ 1\over 3}e^{(t+c)}+{8\over 3} \)

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