If \(\tan x=\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta} \), \(\frac{\pi}{4}<\theta<\frac{\pi}{2} \), then what is √2 sin x equal to?
1
sin θ + cos θ
2
sin θ - cos θ
3
\(\frac{\sin \theta+\cos \theta}{2}\)
4
\(\frac{\sin \theta-\cos \theta}{2}\)