The solution of the following differential equation
sec2y \(\frac{dy}{dx}\) + 2x tan y = x3 is :
1
tan y = \(\frac{1}{2}\)(x2 + 1) + c \(e^{-x^{2}}\)
2
tan y = \(\frac{1}{2}\)(x2 − 1) + c \(e^{-x^{2}}\)
3
cot y = \(\frac{1}{2}\)(x2 + 1) + c \(e^{-x^{2}}\)
4
tan y = \(\frac{1}{2}\)(x2 − 1) + c \(e^{x^{2}}\)
5
Not Attempted