If a + b + c = 3, a2 + b2 + c2 = 6
and \(\frac{1}{a}\) + \(\frac{1}{b}\) + \(\frac{1}{c}\) = 1, where a, b and c ≠ 0, then abc = ?
1
1
2
\(\frac{5}{2}\)
3
\(\frac{3}{2}\)
4
\(\frac{1}{2}\)
If a + b + c = 3, a2 + b2 + c2 = 6
and \(\frac{1}{a}\) + \(\frac{1}{b}\) + \(\frac{1}{c}\) = 1, where a, b and c ≠ 0, then abc = ?