Equation of hyperbola whose eccentricity is 4/3 and foci at (±3, 0) is 6x2 - 9y2 = k2. What is the value of k?

1
\(2\sqrt 6 \)
2
\(3\sqrt 6 \)
3
\(4\sqrt 6 \)
4
\(\frac{9\sqrt 6}{4}\)
5
Not Attempted

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