Solve the partial differential equation q2 = 4z2p2(1 – p2)

1
2z2 = a2 - (2x + 2ay + b)2 ; where a and b are arbitrary constants
2
4z2 = a2 + (2x + 2ay + b)2 ; where a and b are arbitrary constants
3
2z2 = a2 + (2x + 2ay + b)2 ; where a and b are arbitrary constants
4
4z2 = a2 - (2x + 2ay + b)2 ; where a and b are arbitrary constants
5
Not Attempted

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